[문제 링크]
http://projecteuler.net/problem=6
[문제 원본]
The sum of the squares of the first ten natural numbers is,
12 + 22 + … + 102 = 385
The square of the sum of the first ten natural numbers is,
(1 + 2 + … + 10)2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 385 = 2640.
Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
[문제 설명]
1~100까지 합의 제곱 에서 1의 제곱 더하기 2의 제곱 더하기 … 100의 제곱을 더한값을 뺀 값을 구하라.
[소스 코드]
import time sTime = time.clock() sqrAndSum = 0 sumAndSqr = 0 for i in range(1, 101): sqrAndSum = sqrAndSum + (i*i) sumAndSqr = 0 for i in range(1, 101): sumAndSqr = sumAndSqr + i sumAndSqr = (sumAndSqr * sumAndSqr) print("Result=", sumAndSqr - sqrAndSum, "time=", (time.clock() - sTime) * 100)
[출력 결과]
(‘Result=’, 25164150, ‘time=’, 0.007399999999999768)